Part of: Miscellaneous Indian Gk set 121

Which of the following number is divisible by 2?

Category: Miscellaneous Indian Gk

Hint: Check the last digit of each number.

Correct Answer: C) 7890

Exam Relevance: CBSE, ICSE, State Board Exams, Competitive Exams

Difficulty: Easy

Explanations:

The concept of divisibility by 2 is a fundamental rule in number theory. It is based on the property that any number which is a multiple of 2 is an even number. Even numbers are characterized by their last digit being one of the following: 0, 2, 4, 6, or 8. This rule is derived from the fact that the number 2 is the smallest prime number and the basis for the binary system, which is widely used in computing and digital electronics.

To determine if a number is divisible by 2, one only needs to look at the last digit of the number. If the last digit is even, the entire number is divisible by 2. Conversely, if the last digit is odd, the number is not divisible by 2. This rule simplifies the process of checking divisibility, as it does not require performing the actual division.

Let's apply this rule to the given options:

Option A: 6483

The last digit of 6483 is 3, which is an odd number. Therefore, 6483 is not divisible by 2.

Option B: 2967

The last digit of 2967 is 7, which is an odd number. Therefore, 2967 is not divisible by 2.

Option C: 7890

The last digit of 7890 is 0, which is an even number. Therefore, 7890 is divisible by 2.

Option D: 1235

The last digit of 1235 is 5, which is an odd number. Therefore, 1235 is not divisible by 2.

Thus, the correct answer is Option C: 7890, as it is the only number among the given options that ends with an even digit, making it divisible by 2.

Option Analysis:
  • Option A: This option is incorrect because the last digit of 6483 is 3, which is an odd number. Therefore, 6483 is not divisible by 2.
  • Option B: This option is incorrect because the last digit of 2967 is 7, which is an odd number. Therefore, 2967 is not divisible by 2.
  • Option C: This option is correct because the last digit of 7890 is 0, which is an even number. Therefore, 7890 is divisible by 2.
  • Option D: This option is incorrect because the last digit of 1235 is 5, which is an odd number. Therefore, 1235 is not divisible by 2.

Mnemonic: Even numbers end in 0, 2, 4, 6, or 8.

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