📚 Part of: Ancient Indian Geography & Divisibility Rules Mcqs

Which of the following number is divisible by 2?

Category: Miscellaneous Indian Gk

Correct Answer: C) 7890.

Exam Relevance: UPSC, SSC, Bank PO, CLAT, MAT

Difficulty: Easy

Concept notes:

Divisibility by 2 is a fundamental concept in basic arithmetic. A number is divisible by 2 if it is an even number, which means it ends in 0, 2, 4, 6, or 8. This rule is useful in quickly determining if a number can be evenly divided by 2 without performing the actual division.

Common Mistakes:
  • Confusing divisibility by 2 with divisibility by other numbers, such as 3 or 5.
  • Not recognizing that only the last digit of a number determines its divisibility by 2.
  • Assuming that all numbers ending in 0 are divisible by 2, but forgetting that other digits (2, 4, 6, 8) also qualify.
Explanation:

The concept of divisibility by 2 is a fundamental principle in basic arithmetic and is often tested in various competitive examinations in India, such as the UPSC, SSC, Bank PO, CLAT, and MAT. Understanding this concept is crucial for quickly determining whether a number can be evenly divided by 2 without performing the actual division.

A number is divisible by 2 if it is an even number. An even number is defined as any integer that is exactly divisible by 2, meaning it can be expressed as 2n, where n is an integer. The key characteristic of even numbers is that they end in one of the digits 0, 2, 4, 6, or 8. Conversely, odd numbers end in 1, 3, 5, 7, or 9 and are not divisible by 2.

To determine if a number is divisible by 2, you only need to look at the last digit of the number. This is because the divisibility of a number by 2 depends solely on its last digit. For example, the number 7890 ends in 0, which is an even digit, so it is divisible by 2. On the other hand, the number 6483 ends in 3, which is an odd digit, so it is not divisible by 2.

In the given options, 6483, 2967, and 1235 are all incorrect because they end in odd digits (3, 7, and 5, respectively). The only number that ends in an even digit is 7890, which ends in 0. Therefore, 7890 is the correct answer as it is divisible by 2.

Understanding this rule helps in quickly identifying even and odd numbers, which is a basic but essential skill in arithmetic and is often tested in various competitive examinations. It is important to remember that the divisibility by 2 is determined solely by the last digit of the number, and this rule applies to all integers, regardless of their size.

Option Analysis:
  • Option A: 6483 is not divisible by 2 because it ends in 3, which is an odd number. The rule for divisibility by 2 states that a number must end in an even digit (0, 2, 4, 6, or 8) to be divisible by 2. Therefore, 6483 is incorrect.
  • Option B: 2967 is not divisible by 2 because it ends in 7, which is an odd number. The rule for divisibility by 2 states that a number must end in an even digit (0, 2, 4, 6, or 8) to be divisible by 2. Therefore, 2967 is incorrect.
  • Option C: 7890 is divisible by 2 because it ends in 0, which is an even number. The rule for divisibility by 2 states that a number must end in an even digit (0, 2, 4, 6, or 8) to be divisible by 2. Therefore, 7890 is correct.
  • Option D: 1235 is not divisible by 2 because it ends in 5, which is an odd number. The rule for divisibility by 2 states that a number must end in an even digit (0, 2, 4, 6, or 8) to be divisible by 2. Therefore, 1235 is incorrect.

Mnemonic: Even numbers end in 0, 2, 4, 6, or 8.

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